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a) 12x² - 7x + 1
= we can find two numbers such that pq = 12 x 1 = 12 and p + q = -7
= Here, 12x² - 7x + 1 = 12x² - 4x - 3x + 1
= 4 x ( 3x - 1 ) - 1 ( 3x - 1 )
= ( 3x - 1 ) ( 4x - 1 )
b) → 2x² + 6x + 1x + 3 = 0
→ 2x(x + 3) + 1(x + 3) = 0
→ (2x + 1)(x + 3) = 0
c) 6x² + 5x -6
6x² + 9x - 4x -6
3x (2x + 3) -2(2x+3)
(3x-2)(2x+3)
d) Now, 3x² - x - 4
= 3x² - (4 - 3)x - 4
= 3x² - 4x + 3x - 4
= x (3x - 4) + 1 (3x - 4)
= (3x - 4) (x + 1).
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