Question

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Answer 1

Answer:

Here, mass ob block A, m

A

=10kg

Mass of block B,m

B

=15kg

Coefficient of friction between and the blocks and surface, μ=0.2

Applied force = 200 N

Froce of friction on A =μN

A

=μm

A

g=0.2×10×10=20N

Force of friction on B =μN

B

=μm

B

g==0.2×15×10=30N

Taking two blocks forming one system, therefore net force acting on the blocks is

F=200-20-30=150 N

Let a be common acceleration of the system.

∴a=

m

A

+m

B

F

=

(10+15)kg

150N

=6ms

−2

Answer 2

Answer:

ajib ho yar app toa..... apko math pasand hai.......