Question

please answer this fast​

Answer 1

Answer:

$x = -3$

Step-by-step explanation:

Given that,

$(\frac{7}{3} )^4$ x $(\frac{7}{3} )^{3x}$ x $(\frac{7}{3} )^{-2}$ = $(\frac{7}{3} )^{(2x - 1)}$

$=>(\frac{7}{3} )^{(4 + 3x -2)}$  = $(\frac{7}{3} )^{(2x - 1)}$  [Using the $a^m . a^n = a^{(m+n)}$ formula of indices]

$=> \frac{(\frac{7}{3} )^{(3x + 2)}}{(\frac{7}{3} )^{(2x - 1)}} = 1$  [dividing both sides by $(\frac{7}{3} )^{(2x - 1)}$]

$=> (\frac{7}{3} )^{[(3x + 2) - (2x - 1)]} = (\frac{7}{3} )^{0}$  [Using the $\frac{a^m}{a^n} = a^{(m-n)} ; a^0 = 1$ formulas

                                              of indices]

∴ $3x + 2 - 2x + 1 = 0$

∴ $x = -3$