Question

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Answer 1

Answer:

20

____

9

Step-by-step explanation:

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Answer 2

$\huge\tt\green{ANSWER:}$

Let the numbers be X and (X - 9).

As we know the sum of their reciprocal is

We can say,

$\frac{1}{x} + \frac{1}{9 - x} = \frac{9}{20}$

Adding 1/x and 1/(9-x),

$= > \frac{9 - x + x}{x(9 - x)} = \frac{9}{20}$

cancelling - x and + x,

$= > \frac{9}{x(9 - x)} = \frac{9}{20}$

cross multiplying,

$= > 9(20) = 9x(9 - x)$

$= > 180 = 81x { - 9x}^{2}$

${ - 9x}^{2} + 81x - 180$

Dividing the quadratic both sides equation by (-1),

$= > \frac{ { - 9x}^{2} + 81x - 180}{ - 1} = \frac{0}{ - 1}$

$= > {9x}^{2} - 81x + 180 = 0$

Putting the values of a, b and c in the quadratic formula,

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