Question

Please answer this fast ​

Answer 1

....Answer....

Given :

v = 15 m/s. (Final point velocity)

S = 60 m.

t = 6 seconds.

u = ?(Initial point velocity)

Explanation :

From First Kinematic equation.

v=u+at

rearranging.

a = (v-u/t) --------- (1)

Now, Using second kinematic equation.

S = ut + 1/1at²

Substituting the values of acceleration in the equation, time and distance value.

60 = u × 6 + ¹ x 26×6²

60 = u × 6+1 × v 1 2 v − u × Ø

60= 6u + (15 - u) x 3

60-6u + 45-3u

60 - 45 = 3u

u= 15

u = 5m/s