Question

please answer this fast
I'm in great need​

Answer 1

Step-by-step explanation:

1) x^12-1/x^12

= (x^6)^2-(1/x^6)^2

= (x^6+1/x^6)(x^6-1/x^6)

= (x^6+1/x^6)[(x^3)^2-(1/x^3)^2]

= (x^6+1/x^6)(x^3+1/x^3)(x^3-1/x^3)

2) 343+64x^3

= (7)^3+(4x)^3

= (7+4x)(49-28x+16x^2)

3) a^3b^3-3√3c^3

= (ab)^3-(√3c)^3

= (ab-√3c)(a^2b^2+√3abc+3c^2)

Answer 2

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1) x^12-1/x^12

= (x^6)^2-(1/x^6)^2

= (x^6+1/x^6)(x^6-1/x^6)

= (x^6+1/x^6)[(x^3)^2-(1/x^3)^2]

= (x^6+1/x^6)(x^3+1/x^3)(x^3-1/x^3)

2) 343+64x^3

= (7)^3+(4x)^3

= (7+4x)(49-28x+16x^2)

3) a^3b^3-3√3c^3

= (ab)^3-(√3c)^3

= (ab-√3c)(a^2b^2+√3abc+3c^2)

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