Question

please answer this fast, i need this​

Answer 1

Answer:

1 / a

Step-by-step explanation:

( I am guessing that you actually meant to write "7+2n", not "7+2x".  I hope that's right! )

The key rules we need are:

• ( xᵃ )ᵇ = xᵃᵇ
• xᵃ xᵇ = xᵃ⁺ᵇ
• xᵃ / xᵇ = xᵃ⁻ᵇ

Using these, we get

$\displaystyle\frac{a^{7+2n}\ (a^2)^{3n+2}}{(a^4)^{2n+3}}\\\\=\frac{a^{7+2n}\ a^{2(3n+2)}}{a^{4(2n+3)}}\\\\=\frac{a^{7+2n}\ a^{6n+4}}{a^{8n+12}}\\\\=\frac{a^{(7+2n)+(6n+4)}}{a^{8n+12}}\\\\=\frac{a^{8n+11}}{a^{8n+12}}\\\\=a^{(8n+11)-(8n+12)}\\\\=a^{-1}\\\\=\frac1a$

Hope that helps!