Question

please answer this fast it's urgent.

abcd is a square. cde and bdf are two equilateral triangles. find the ratio between the areas of triangle edc and fbd.
THANK YOU!​

Answer 1

Step-by-step explanation:

Given, ABCD is a square. DCE is an equilateral triangle.

ABCD is a square,

AB=BC=CD=DA

DCE is an equilateral triangle,

DC=DC=CE

Hence, AB=BC=CD=DA=CE=DC

Now, In △ADE,

AD=DE

Thus, ∠AED=∠DAE=x

∠ADE=∠ADC+∠EDC

∠ADE=90+60

∠ADE=150 ∘

Sum of angles of triangle ADE = 180

∠ADE+∠AED+∠DAE=180

150+x+x=180x=15 ∘

Hence, ∠DAE=15 ∘