Math, asked by sujanaak02, 4 months ago

please answer this fastly​

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Answered by PharohX
3

Answer:

SOLUTION :-

THIS CAN BE SOLVED AS -

 \sf \:  \frac{ {2}^{n}  \{1.3.5.7.........(2n - 1) \}}{ n!}  \\

Multiply and divide with (2×4×6×8.........2n)

  = \sf \:  \frac{ {2}^{n}  \{1.2.3.4.5.6.7.........(2n - 1).2n \}}{(2.4.6.8...........2n) n!}  \\

 \sf =  \frac{ {2}^{n}  \{2n ! \}}{ {2}^{n}(1.2.3.4........n)n! }  \\

 \sf \:  =  \frac{2n!}{n! \: .n!}  \\

 \sf \:  =  \frac{2n!}{(n!)^{2} }  \\

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