please answer this
find the value of n if 2^10=2^-2*2^3n
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Answer:
n = 4
Step-by-step explanation:
Given: 2¹⁰ = 2⁻² * 2³ⁿ
Divide both sides by '2⁻²'
⇒ (2¹⁰/2⁻²) = (2⁻² * 2³ⁿ/2⁻²)
⇒ (2¹⁰/2⁻²) = 2³ⁿ
We know that (xᵃ/xᵇ) = (xᵃ⁻ᵇ)
⇒ 2¹⁰⁻⁽⁻²⁾ = 2³ⁿ
⇒ 2¹⁰⁺² = 2³ⁿ
⇒ 2¹² = 2³ⁿ
We know that aⁿ = aˣ, then n = x.
⇒ 12 = 3n
Divide both sides by '3', we get
⇒ (12/3) = (3n/3)
⇒ n = 4
Therefore, the value of n = 4.
Hope it helps!
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