Question

please answer this friends​

Answer 1

Answer:

LHS

$\frac{ \cot(a) + \tan(b) }{ \cot(b) + \tan(a) } = \frac{ \frac{ \cos(a) }{ \sin(a) } + \frac{ \sin(b) }{ \cos(b) } }{ \frac{ \cos(b) }{ \sin(b) } + \frac{ \sin(a) }{ \cos(a) } } =$

$\frac{ \frac{ \cos(a) \cos(b) + \sin(a) \sin(b) }{ \sin(a) \cos(b) } }{ \frac{ \cos(a) \cos(b) + \sin(a) \sin(b) }{ \cos(a) \sin(b) } } = \frac{ \cos(a) \sin(b) }{ \sin(a) \cos(b) } =$

$\cot(a) \tan(b) \: rhs.$

Answer 2

Answer:

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