Question

please answer this friends...

Answer 1

See the above picture ......

Answer 2

$Given : \frac{ 9^{ \frac{1}{3} * 27^{- \frac{1}{2} } } }{3^ \frac{1}{6} * 3^{- \frac{2}{3} } }$

$= \ \textgreater \ \frac{ (3^2)^{ \frac{1}{3} } * (3^3)^{ \frac{-1}{2} } }{ 3^{ \frac{-1}{2} } }$

$= \ \textgreater \ \frac{ 3^{ \frac{2}{3} } * (3^3)^{- \frac{1}{2} } }{ 3^{- \frac{1}{2} } }$

$= \ \textgreater \ 3^{ \frac{2}{3} - (- \frac{1}{2} )} * (3^3)^- \frac{1}{2}$

$= \ \textgreater \ 3^{ \frac{7}{6} } * 3^ \frac{-3}{2}$

$= \ \textgreater \ 3^{- \frac{1}{3} }$

1/3.



Hope this helps!