please answer this guys urgently.
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1)
Let the second no. be x
ATQ,
(x+20)/2=13
x+20=13×2
x=26-20
x=6
Thus,
Second no. is 6.
2)
Let the third no. be y
ATQ,
(x+10+15)/3=19
x+25=19×3
x=57-25
x=32
Thus,
Third no. is 32
HOPE IT WILL HELP U...
PLZ MARK IT AS BRAINLIEST ANSWER..
Let the second no. be x
ATQ,
(x+20)/2=13
x+20=13×2
x=26-20
x=6
Thus,
Second no. is 6.
2)
Let the third no. be y
ATQ,
(x+10+15)/3=19
x+25=19×3
x=57-25
x=32
Thus,
Third no. is 32
HOPE IT WILL HELP U...
PLZ MARK IT AS BRAINLIEST ANSWER..
Anonymous:
frnd did good bt did complicated
not at all
it's not complicated, it's the correct method.
thanx pakhi
you are welcome sis
: )
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