Please answer this I am having a problem in this
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Step-by-step explanation:
1)in triangle ADB and ADC,
<ADB=<ADC (90°)
<ABD=<ACD (isosceles )
AD is a median to <A, so <BAD=<CAD
2) triangle ADB and triangle ADC are equal because all the angles are equal.
3) angle P is equal to angle C as it is isosceles TRIANGLE.
4) BD = CD, as the triangle is congruent by AAA, SO THE SIDES ARE SIMILAR
*use the word congruent in every step if u can...
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i.
a. angle adb and angle adc
b. side ab and side bc
c. side ad and side ad
ii. yes, triangle adb is congruent to triangle adc
by sas congruency rule.
iii. yes, they are equal. because the angles' opposite sides ac and ab respectively are equal.
iv. yes, because of corresponding parts of congruent triangles rule.
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