please answer this I'll mark you as brainliest
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hope my answer will help you
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Step-by-step explanation:
here
consider a triangle ADP
in AD^P
AD=AP+DP(BY PYTHAGORUS RULE)
^p=90°(RIGHT ANGLED TRIANGLE)
therefore,
AD=AP+PD
consider triangleQBC
^QBC
BC=QB+QC(BY PYTHAGORUS THEORAM)
^Q=90°(RIGHT ANGLED TRIANGLE)
SO BC=QB+BC
then AD=BC
AP=BC
PD=BC
so triangleADP=CBQ
2)
SO,ADP=CBQ
3)DP=DQ
MARK ME AS A BRAINLIEST
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