Question

Please answer this ,

I'm having exams tomorrow,

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Answer 1

Proof:(◇=triangle)

In ◇AOB &◇AOC

AB=AC (Given)

AO=AO(Common)

OB=OC(sides opposite to equal angles)

Therefore, ◇AOB is congruent to ◇AOC(By SSS Rule)

So, <OAB=<OAC (CPCT)

Hence, OA bisects <A.

Proved.

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