please answer this
I'm very confused I don't know how to solve it
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sin4x + cos2x = (1-cos2x )2 + cos2x
= 1 + cos4x -2cos2x + cos2x
= 1+ cos4x -cos2x
= 1/4 + 3/4 + cos4x - cos2x
=(cos2x −12)2 +34 =(2cos2x −12)2 +34=(cos2x)24+34 As (cos2x)2 will lies between [0,1]So above expression has minimum value when (cos2x)2 = 0 And maximum value when (cos2x)2 = 1 Hence the range is [3/4,1]
hope it helps u dear
= 1 + cos4x -2cos2x + cos2x
= 1+ cos4x -cos2x
= 1/4 + 3/4 + cos4x - cos2x
=(cos2x −12)2 +34 =(2cos2x −12)2 +34=(cos2x)24+34 As (cos2x)2 will lies between [0,1]So above expression has minimum value when (cos2x)2 = 0 And maximum value when (cos2x)2 = 1 Hence the range is [3/4,1]
hope it helps u dear
Anonymous:
mark it brainliest
but the answer is [3/4,1]
so I can't mark it as brainliest
kk I'm editing it
please send me the solution photo so that I can understand more
now its clear
ya it is now clear
how do I mark it as brainliest
kk so mark it
kk
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