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from the given diagram , find the length of the sides PR and SR by using pythagoras theorem.
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Step-by-step explanation:
Given Data :- RQ=15cm,PQ=20cm,PS=24cm,90° at S&Q.
To find :- SR & PR.
There are 2 right angle triangle
i.∆PQR.
In this ∆PQR.PR is hypotenuse
By Pythagoras Theorem.
(hypo)²=(S1)²+(S2)²
PR²=PQ²+RQ²
PR²=(20)²+(15)²
PR²=400+225
PR²=625
√PR²=√625
(PR=25cm) ---------(1)
ii.∆PSR.
In this ∆PSR.PR is hypotenuse.
By Pythagoras Theorem.
(hypo)²=(S1)²+(S2)²
PR²=PS²+SR²
(25)²=(24)²+(SR)² ------( By 1 )
625=576+(SR)²
625-576=(SR)²
(SR)²=625-576
(SR)²=49
√SR²=√49
(SR=7cm.)
[PR=25cm & SR=7cm]
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