Math, asked by ashokc454, 2 months ago

please answer this i will mark as brilianist who gave the write answer​

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ashokc454: please answer with procedure

Answers

Answered by priya2161
2

Answer:

a^3-4a^2+5a-6-(a^2-2a+1)

a^3-4a^2+5a-6-a^2+2a-1

a^3-5a^2+7a-7


ashokc454: thanks
Answered by Raushanstudent
2

Answer:

a³-5a²+6a-7.

Step-by-step explanation:

Le the required number to be subtracted be x.

Then, a³-4a²+5a-6-x=a²-2a+1

=>a³-4a²+5a-6-(a²-2a+1)=x

=>a³-4a²+5a-6-a²+2a-1=x

=>x=a³-5a²+6a-7

Therefore, the required number is a³-5a²+6a-7.

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