please answer this if you know
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Hope this helps you ..
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kshitiz36:
this is wrong
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HEYA! HERE IS YOUR ANSWER:
Given,
The equations have unique solutions.
If the equation has unique solution the comparison of ratios will be:
a1/a2 is not equal to b1/b2
1) 2x+3y-5=0
kx-6y-8=0
In the above equations:
a1 = 2 ; a2 = k ; b1 = 3 ; b2 = -6
a1/a2 is not equal to b1/b2
2/k is not equal to 3/-6
{Cross Multiple}
2*-6 = 3*k
-12 = 3k
k = -12/3
k = -4
2) 2x+ky=1
5x-7y=5
In the above equations:
a1 = 2 ; a2 = 5 ; b1 = k ; b2 = -7
a1/a2 is not equal to b1/b2
2/5 is not equal to k/-7
{Cross multiple}
2*-7 = k*5
-14 = 5k
k = 5/-14
HOPE THIS HELPS YOU BUDDY✌️
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