Question

please answer this if you know​

Answer 1

Answer:

1 because whose power is 0 =1

Answer 2

Answer:-

• 1

Question:-

$= \bf \: \frac{ {sin}^{3} \theta \: + {cos}^{3} \theta \: }{sin \theta \: + \: cos \theta \: } + \sin \theta \: cos \theta \: =$

Given:-

• $\bf \: \frac{ {sin}^{3} \theta \: + {cos}^{3} \theta \: }{sin \theta \: + \: cos \theta \: } + \sin \theta \: cos \theta \: =$

Solution:-

$⇒ \frac{(sin \theta \: + \: cos \theta \: )( {sin}^{2} \theta \: + {cos}^{2} \theta \: - sin \theta \: cos \theta \: ) }{(sin \theta \: + \: cos \theta)} \\ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ + sin \theta \: cos \theta \:$

$⇒(1 - sin \theta \: cos \theta \: ) + sin \theta \: cos \theta \:$

$⇒1 - sin \theta \: cos \theta \: + sin \theta \: cos \theta \:$

$⇒ 1$

Step-by-step explanation:

Learn more:-

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin \theta \: & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \theta & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan \theta & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm not \: defined\\ \\ \rm cosec \theta & \rm not \: defined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec \theta \: & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm not \: defined \\ \\ \rm cot \theta& \rm not \: defined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$