Question

please answer this immediately​

Answer 1

Answer:

In ∆ ABC

AB=AC (given)

P and Q are the midpoints on AB and AC.

So, AP =BP

and AQ=QC

Now in ∆BCP and ∆CBQ

BC=BC (Common)

Angle B=Angle C

PB = QC (P and Q are midpoint)

∆BCP~= ∆CBQ (By SAS)

Hope it's help.