Math, asked by poornadithya, 1 year ago

please answer this
immediately

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Answered by 9552688731
2
(a+b,b+c)
X1 = a+b
Y1= b+c

(a-b,c-b)
X2 = a-b
Y2 = c-b

distance = d = ?
d = √(x2-x1)²+(y2-y1)²

d = √(a-b-(a+b))+(c-b-(b+c))

d = √(a-b-a-b)²+(c-b-b-c)

d = √(-2b)²+(-2b)²

d = √(4b²)+(4b²)

d = √8b²

d = 2b√2 unit
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