Question

Please answer this it a little tricky. Where do we need to add 8

Answer 1

Answer:

Step-by-step explanation:

Let one digit of the number be x , then its ten  digits digits will be (8−x) .  

number =10(8−x)+x  

              =80−10x+x  

               =80−9x

Now if digits are reversed  , then Number obtained  

                 =10x+(8−x)

                  =10x+8−x

                   =9x+8

so,

(80−9x)+18=9x+8

        98−9x=9x+8  

        90=18x

          x=5

given number  =80−9x

                        =80−9×5      

                         =80−45  

                          =35  

to check you answer,

35=18=53