Question

Please answer this it for urgent

Answer 1

$\Large{\underline{\underline{\mathfrak{\tt{\red{Solution(10).}}}}}}$

$\Large{\underline{\mathfrak{\tt{\orange{Given}}}}}$

• Radius of big Circle = 6 cm
• Radius of small Circle = 3 cm

$\Large{\underline{\mathfrak{\tt{\orange{Find}}}}}$

• Area of shaded region

$\Large{\underline{\underline{\mathfrak{\tt{\red{Explanation}}}}}}$

$\Large{\underline{\mathfrak{\tt{\orange{Important\:Formula}}}}}$

$\small\boxed{\underline{\green{\tt{\:Area_{Circle}\:=\:\pi.(Radius)^2}}}}$

So, First Calculate Area of Big Circle

$\mapsto\tt{\:Area\:of\:big\:Circle\:=\:\pi\times(6)^2} \\ \\ \mapsto\tt{\:Area\:of\:big\:Circle\:=\:\dfrac{22}{7}\times6\times6} \\ \\ \mapsto\tt{\orange{\:Area\:of\:big\:Circle\:=\:\dfrac{792}{7}\:cm^2}}$

Now, Calculate Area of Small Circle

$\mapsto\tt{\:Area\:of\:Small\:Circle\:=\:\pi\times(3)^2} \\ \\ \mapsto\tt{\:Area\:of\:Small\:Circle\:=\:\dfrac{22}{7}\times3\times3} \\ \\ \mapsto\tt{\orange{\:Area\:of\:Small\:Circle\:=\:\dfrac{198}{7}\:cm^2}}$

But, Area for shaded region

we Subtract Area of Small Circle by Area of Big Circle .

So,

$\mapsto\tt{\red{\:Area\:of\:shaded\:region\:=\:Area_{big\:circle}\:-\:Area_{small\:circle}}} \\ \\ \small\tt{\green{\:\:\:\:\:\:Keep\:All\:Above\:Values}} \\ \\ \mapsto\tt{\:Area\:of\:Shaded\:region\:=\:\dfrac{792}{7}\:-\:\dfrac{198}{7}} \\ \\ \mapsto\tt{\:Area\:of\:shaded\:region\:=\:\dfrac{792-198}{7}} \\ \\ \mapsto\tt{\red{\:Area\:of\:shaded\:region\:=\:\dfrac{594}{7}\:cm^2}} \\ \\ \Large\tt{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(Ans.)}}$

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