Math, asked by bijaylaxmisahoo897, 1 month ago

please answer this it's really important​

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Answered by Anonymous
1

iv) Thus, the present age of Jane’s younger sister is 12 years.

And of Jane’s is 18 years.

v) Therefore the sides are = 24 cm,32, cm and 40 cm.

Step-by-step explanation:

iv) Let the age of Jane’s younger sister is x.

Age of Jane will be x + 6

As per the question, after 10 years the sum of their ages will be 50.

After 10 years,

age of Jane = x + 16

age of her younger sister = x + 10

Therefore,

x + 16 + x +10 = 50

2x + 26 = 50

2x = 24

x = 12

Thus, the present age of Jane’s younger sister is 12 years.

And of Jane’s is 12+6 = 18 years.

v) Hypotenuse^2 = base^2 + perpendicular^2

Therefore, the sides are in the ratio of

3 : 4 : 5

Sum of the ratios = 3 +4 +5 = 12

Perimeter of triangle = 96 cm

Therefore the sides are = (96*3/12), (96*4/12), (96*5/12) = 24 cm,32, cm and 40 cm.

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