Question

please answer this It's urgent ​

Answer 1

Step-by-step explanation:

In ∆ADC,

60°+70°+c = 180° [Angle sum property]

c = 50°

a + 30° = c [ Exterior angle property]

a + 30° = 50°

a = 20°

In ∆ABD,

a + b + 30° = 180°

20° + b + 30° = 180°

b = 130°

Hope this answer helped you buddy

Please mark my answer as brainliest

Please follow me... I will follow you back

Answer 2

Step-by-step explanation:

In ABC

angle A+angle B+ angle C=180°

60°+70°+c=180°

c=(180-130)°

c=50°

angle BDA+angle ADC=180°(linear pair)

b+50°=180°

b=130°

in fig ABD

angle A+ angle B+ angle D=180°

30°+130°+a=180°

a=180°-160°

a=20°

I hope it helps you....

plz mark me as Brainliest