please answer this it's urgent
Attachments:
Answers
Answered by
1
it will take a bit time
Answered by
2
Given 1445 > 1190.
(1) 1445 = 1190 * 1 + 255.
The remainder is not equal to 0. use division algorithm to 1190 and 255.
(2) 1190 = 255 * 4 + 170
The remainder is not equal to 0.use division algorithm to 255and 170.
(3) 255 = 170 * 1 + 85
The remainder is not equal to 0.use division algorithm to 170 and 85.
(4) 170 = 85 * 2 + 0.
The remainder is 0.
Therefore the HCF of 1190 and 1445 = 85.
Now,
85 = 255 - 170
= (1445 - 1990) - (1190 - 255 * 4)
= 1445 - 1990 - 1190 + 255 * 4
= 1445 - 1990 * 2 + (1445 - 1190) * 4
= 1445 - 1990 * 2 + 1445 * 4 - 1190 * 4
= 1445 * 5 - 1190 * 6
= 1190(-6) + 1445(5)
Therefore m = -6 and n = 5.
Hope this helsp!
(1) 1445 = 1190 * 1 + 255.
The remainder is not equal to 0. use division algorithm to 1190 and 255.
(2) 1190 = 255 * 4 + 170
The remainder is not equal to 0.use division algorithm to 255and 170.
(3) 255 = 170 * 1 + 85
The remainder is not equal to 0.use division algorithm to 170 and 85.
(4) 170 = 85 * 2 + 0.
The remainder is 0.
Therefore the HCF of 1190 and 1445 = 85.
Now,
85 = 255 - 170
= (1445 - 1990) - (1190 - 255 * 4)
= 1445 - 1990 - 1190 + 255 * 4
= 1445 - 1990 * 2 + (1445 - 1190) * 4
= 1445 - 1990 * 2 + 1445 * 4 - 1190 * 4
= 1445 * 5 - 1190 * 6
= 1190(-6) + 1445(5)
Therefore m = -6 and n = 5.
Hope this helsp!
arya57:
no
Similar questions