Please answer this.....It's very important...
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Answer:
Step-by-step explanation:
GIVEN:
∠AOQ= 58°
∠ABQ= ½ ∠AOQ
∠ABQ= ½(58°)
∠ABQ= 29°
∠BAT= 90°
(The tangent at any point of a circle is perpendicular to the radius through the point of contact)
∠BAT+ ∠ABQ (∠ABT) +∠ ATQ = 180°
∠ATQ =∠BAT -∠ABQ
∠ATQ= 90° - 29° = 61°
Hence, ∠ATQ= 61°
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Hope this will help you....
adi487510:
JAHA ans start hai vaha
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