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Q) Haemoglobin contains 0.334 % of Iron (Fe) by weight. The molecular weight of Hgb is 67200u. Calculate the number of Fe atoms in 1 molecule of Hgb.
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Percentage of Fe = 0.33%
molecular weight of haemoglobin
Weight of Fe present = (0.33/100) × 67200
= 221.8
one Fe weighs 55.8 g
Therefore, 221.8/55.8 = 4Hence,
4 atoms of iron are present in one molecule of haemoglobin.
Percentage of Fe = 0.33%
molecular weight of haemoglobin
Weight of Fe present = (0.33/100) × 67200
= 221.8
one Fe weighs 55.8 g
Therefore, 221.8/55.8 = 4Hence,
4 atoms of iron are present in one molecule of haemoglobin.
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