Computer Science, asked by queen264, 2 months ago

please answer this its from aakash​

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Answered by diksha246876
1

Answer:

Maximum frequency ( F1) =12

(F0) frequency of proceding class = 7

(F2) Frequency of succeeding class =8

modal class =9--12

L= lower limit= 9

h= upper limit --lower limit = 12-9 =3

mode = L + (F1 - F0)/2F1 - F2 -F0) × h

by putting values

9+ ( (12-7) /2×12 -7 -8) ×3

9+ (5/24 -15)×3

9+(5/9)×3

9+5/3

by taking Lcm of 9

9×3/1×3 + 5/3

27/3 + 5/3

27+5/3

32/3

mode = 1.66

Explanation:

Hope this will help!

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