Question

Please answer this
Its urgent ​

Answer 1

Answer:

I will represent th powers as norma numbers, like this: 3/7 2

Step-by-step explanation:

[(3/7) -2] -3

When two powers are presented like this, one inside a bracket and on outside, we multiply them

so:

= 3/7 6

Answer 2

Answer:

$(( \frac{3}{7} ) {}^{ - {}^{} 2} ) {}^{ - 3} \\ = >$

( a^m )^n = a^mn

$( \frac{3}{7} ) {}^{ - 2 \times( - 3)} \\ = >( \frac{3}{7} ) {}^{6} \\ = > \frac{3 {}^{6} }{7 {}^{6} }$