please answer this its urgent.
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of which class is it?
10th
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Draw ON ⊥AB
Therefore, AN = BN
Also we have PT= PA × PB [By tangent secant property] ---- (1)
Consider ΔONA
OA²= ON²+ AN²---- (2)
Similarly inΔPTO
OP²= OT²+ PT²
That is PT² = OP² - OT²
= ON² + PN² - OA² [Since OA = OT (radii)]
= ON+ PN² – ON² – AN²
⇒ PT² = PN²– AN²----(3)
From (1) and (3), we get
PA × PB = PN²– AN²
PA × PB=T²
what is tangents secant property????
Pls mark it as brainliest
If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
what is tangent secant property???? you have taken the prove as a theorem
ok thanks but that is what we have to prove
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Sorry I have not written Given, to prove and Construction
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