Question

please answer this
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Answer 1

Step-by-step explanation:

first start from ∆ ACD and ∆ABC take boths angles and etc and comine it and see

Answer 2

Answer:

$\fbox\pink{solution \: ↓}$

$\sf\red{In \: ∆ACD \: and \: ∆ABC}</p><p> \\ </p><p> \sf★AC=AC \\ </p><p> \sf★CD=CB \\ </p><p> \: \: \: \: \: \: \: \: \sf\pink{∆CDA=∆CBA=90°}$

By RHS

∆ACD_✓_∆ACD

By CPCT

AD=AB

$\sf\fbox\orange{Hence, it is Proved that AD≈AB}$