Question

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Answer 1

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Answer 2

Answer:

$height = 10m \\ a = 12m \\ b = 20m \\ area \: of \: trapezium = \frac{1}{2} \times sum \: of \: parellel \: sides \times distance \: between \: them \\ = \frac{1}{2} \times 12 + 20 \times 10 \\ = \ \frac{1}{2} \times 32 \times 10 \\ = 1 \times 16 \times 10 \\ = 160 {m}^{2} \\ area \: of \: trapezium = 160 {m}^{2}$

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