Question

Please answer this math question asap!! 30 points and brainliest!!
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MUST SHOW WORK!

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Tan\:A=0.8}}}$

$\green{\tt{\therefore{Tan\:C=1.25}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Length \: of \: AB = 10 \: \\ \\ \tt: \implies Length \: of \: CB = 8 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Tan \: A = ? \\ \\ \tt: \implies Tan \: C = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Tan \: A= \frac{Perpendicular}{Base} \\ \\ \tt: \implies Tan \: A= \frac{CB}{AB} \\ \\ \tt: \implies Tan \: A = \frac{8}{10} \\ \\ \green{\tt: \implies Tan \: A = 0.8} \\ \\ \bold{Similarly:} \\ \tt: \implies Tan \: C= \frac{Perpendicular}{Base} \\ \\ \tt: \implies Tan \: C = \frac{AB}{CB} \\ \\ \tt: \implies Tan \: C = \frac{10}{8} \\ \\ \green{\tt: \implies Tan \:C =1.25} \\ \\ \purple{\bold{Some \: extra \: information}} \\ \pink{\tt{\circ \: Sin \: \theta = \frac{p}{h} }} \\ \\ \pink{\tt{\circ \: Cos \: \theta = \frac{b}{h} }} \\ \\ \pink{\tt{\circ \: Cot \: \theta = \frac{b}{p} }} \\ \\ \pink{\tt{\circ \: Cosec \: \theta = \frac{h}{p} }} \\ \\ \pink{\tt{\circ \: Sec \: \theta = \frac{h}{b} }} \\ \\ \pink{\tt\circ \: {Sin}^{2} \theta + Cos^{2} = 1}$

Answer 2

$</p><p>\huge {\tt{\purple{Hello!!! }}}$

$</p><p>\huge {\fbox{\fbox{\rightarrow {\mathfrak {\pink{Question \: - }}}}}}$

Determine Tan ( A ) and Tan ( C )

$</p><p>\huge {\fbox{\fbox{\rightarrow {\mathfrak {\red{Solution \: - }}}}}}$

$</p><p>\tt{\purple{Tan \: (A) \: = \: 0.8 . }}$

$</p><p>\tt{\purple{Tan \: (C) \: = \: 1.25 . }}$

$</p><p>\tt{\underline {\underline {\orange {Step-By-Step-Explaination \:: }}}}$

$</p><p>\tt{\blue{Given = > }}$

• $\tt{\purple{AB \: = \: 10 \: cm . }}$

• $\tt{\purple{BC\: = \: 8 cm . }}$

We Know That :

$</p><p>\tt{\boxed{\boxed{\green{ Tan \: ( \theta ) \: = \frac{Perpendicular}{Base} }}}}$

=>$</p><p>\tt{\boxed{\boxed{\purple{Tan \: ( \phi) \: = \frac{BC}{AB} = 0.8}}}}$

=>$</p><p>\tt{\boxed{\boxed{\red{Tan \: ( \theta) \: = \frac{AB}{BC} = 1.25}}}}$

$</p><p>\huge{\fbox{\fbox{\rightarrow{\mathfrak{\green{Additional \: Information \: - }}}}}}$

Identities :

$</p><p>\tt{\boxed{\boxed{\red{卐 Sin \: ( \theta ) \: = \frac{P}{H} }}}}$

$</p><p>\tt{\boxed{\boxed{\orange{卐 Cos \: ( \theta ) \: = \frac{B}{H} }}}}$

$</p><p>\tt{\boxed{\boxed{\purple{卐 Cosec \: ( \theta ) \: = \frac{H}{P} }}}}$

$</p><p>\tt{\boxed{\boxed{\red{卐 Sec \: ( \theta ) \: = \frac{H}{P} }}}}$

$</p><p>\tt{\boxed{\boxed{\orange{卐 Tan \: ( \theta ) \: = \frac{P}{B} }}}}$

$</p><p>\tt{\boxed{\boxed{\purple{卐 Cot \: ( \theta ) \: = \frac{B}{P} }}}}$