Question

Please answer this math question asap!! 30 points and brainliest!!
BRAINLIEST ONLY IF YOU SHOW YOUR WORK!
MUST SHOW WORK!

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Tan A=0.8}}}$

$\green{\tt{\therefore{Tan C=1.25}}}$

$\green{\tt{\therefore{\angle A\approx38.7\degree}}}$

$\green{\tt{\therefore{\angle C\approx51.3\degree}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies Length \: CB = 8 \\ \\ \tt: \implies Length \: AB= 10 \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Tan \: A= ? \\ \\ \tt: \implies Tan \: C= ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Tan \: \theta = \frac{Perpendicular}{Base} \\ \\ \tt: \implies Tan \: A = \frac{CB}{AB} \\ \\ \tt: \implies Tan \: A = \frac{8}{10} \\ \\ \green{\tt{:\implies Tan\:A=0.8}}\\ \\ \tt: \implies \angle A = Tan^{ - 1} ( \frac{8}{10} ) \\ \\ \green{\tt: \implies \angle A \approx 38.65 \degree} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies Tan \: \theta = \frac{Perpendicular}{Base} \\ \\ \tt: \implies Tan \: C= \frac{ab}{cb} \\ \\ \tt: \implies Tan \: = \frac{10}{8} \\\\ \green{\tt{:\implies Tan\:C=1.25}} \\\\ \tt: \implies \angle C = Tan^{ - 1} ( \frac{10}{8} ) \\ \\ \green{\tt: \implies \angle C \approx 51.3 \degree}$

Answer 2

$\huge\underline\mathfrak\red{Answer}$

$\green{tanA / =0.8 }$

$\green{tanC / =1.25}$

____________________________________

$\blue{Given}$

in ∆ ABC,

AB=10

BC=8

∠B = 90°

____________________________________

$\orange{to find}$

1) tanA

2) tanB

____________________________________

$\huge\underline\mathfrak\red{Solution}$

As angle B is 90°........................(Given)

I.e. ∆ABC is an Right angled triangle

therefore, using Pythagoras theorem

${ac}^{2} = {ab}^{2} + {bc}^{2}$

therefore,

${ac}^{2} = {8}^{2} + {10}^{2}$

${ac}^{2} = 64 + 100$

${ac}^{2} = 164$

${ac}^{2} = 12.80$

now.....

1). Finding tanA

as we know that,

$\tan( \alpha ) = \frac{Opposite}{Adjacent}$

therefore

⭓⭆$\tan(a) = \frac{bc}{ab}$

⭓⭆$\tan(a) = \frac{8}{10}$

⭓⭆$\tan(a) = 0.8$

⭓⭆$\pink{tanA =0.8 }$

similarly,

⭓⭆$\tan(c) = \frac{ab}{bc}$

⭓⭆$\tan(c) = \frac{10}{8}$

⭓⭆$\tan(c) = 1.25$

⭓⭆$\pink{tanA =1.25 }$

therefore

⭓⭆$\tan(a) = 0.8$

and

⭓⭆$\tan(c) = 1.25$

hope it helps:))

@ItzKittuu