Math, asked by chippywite2004, 1 year ago

please answer this math question from class 9 cbse

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Answered by jaya1012
6
HELLO........FRIEND!!

THE ANSWER IS HERE,

 =  >  \:  \sqrt{ {2}^{ - 1} \times  \sqrt{2}  }  \times  \sqrt{ { \sqrt{2} }^{ - 1}  \times  \sqrt{6} }  \times  \sqrt{ { \sqrt{6} }^{ - 1}   \times 2}

 =  >  \:  \sqrt{ \frac{ \sqrt{2} }{2} }  \times  \sqrt{ \frac{ \sqrt{6} }{ \sqrt{2} } }  \times  \sqrt{ \frac{2}{ \sqrt{6} } }


 =  >  \:  \sqrt{ \frac{ \sqrt{2} }{2} \times  \frac{ \sqrt{6} }{ \sqrt{2} } \times  \frac{2}{ \sqrt{6} }   }


 =  >  \:  \sqrt{1}

=> 1.


:-)Hope it helps u.

chippywite2004: hi
chippywite2004: may I Pls know how to divide √2 by 2
jaya1012: hii
Anudeep1999: just rationaloze the numerator
chippywite2004: ok
jaya1012: we can't divide
chippywite2004: thank you friend
Answered by Prashant24IITBHU
0
and the answer here will be = 1
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