Question

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Answer 1

Please find below the solution to the asked query:

ω0 = x

ω1 = x+18

t = 5s

now,

from first equation of motion for rotational motion:

ω1 = ω0  + α​t

x+18 = x + 5α​

α​ = 3.6 rad/s

now,

I = 1/2 MR2

I = 1/2 ×​ 500 ×​ 0.52

I = 62.5 kgm2

Now,

Torque applied = Iα​ = 62.5×​3.6= 225 N-m