Question

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Answer 1

Answer:

• F₁ = 8 N towards right
• F₂ = 10 N towards right
• F₃ = 12 N towards left

Force F₁ and F₂ are acting in same direction. Therefore, total force in right direction will be sum of the both force.

$\implies F_{(right)} = F_{ 1 } + F_{ 2 }$

$\implies F_{(right)} = 8 + 10$

$\implies \bf F_{(right)} = 18 \: N$

Therefore, total force acting in the right direction is 18 N and also we know that force of 12 N is acting towards left side. By observtion we conclude that 18 N > 12 N. Hence, net force acting on the block is :

$\implies F_{(net)} = F_{ right} - F_{ 3}$

$\implies F_{(net)} = 18 - 12$

$\implies\pink{ \underline{ \boxed{ \bf \orange{F_{(net)} = 6 \: N \: \: \red{(towards \: right)}}}}}$