Question

please answer this
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Answer 1

Answer :-

$\sf\huge \dfrac{y - 6}{4} = \dfrac{2y}{5} - \dfrac{7(y + 3)}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{2y}{5} - \dfrac{7y + 21}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{8y - (7y + 21)}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{8y - 7y - 21}{20}$

$\sf\longrightarrow \dfrac{y - 6}{4} = \dfrac{y - 21}{20}$

$\boxed{\sf Cross \: multiplying \: the \: terms}$

$\sf\longrightarrow 20(y - 6) = 4(y - 21)$

$\sf\longrightarrow 20y - 120 = 4y - 84$

$\sf\longrightarrow 20y - 4y = - 84 + 120$

$\sf\longrightarrow 16y = 36$

$\sf\longrightarrow y = \dfrac{36}{16}$

$\boxed{\underline{\sf \therefore y = \dfrac{9}{4}}}$

Answer 2

Given,

$\frac{y - 6}{4} = \frac{2y}{5} - \frac{7(y + 3)}{20}$

$\frac{y - 6}{4} = \frac{2y}{5} - \frac{7y + 21}{20}$

$\frac{y - 6}{4} = \frac{8y - (7y + 21)}{20}$

$\frac{y - 6}{4} = \frac{8y - 7y - 21}{20}$

$\frac{y - 6}{4} = \frac{y - 21}{20}$

$20(y - 6) = 4(y - 21)$

$20y - 120 = 4y - 84$

$20y - 4y = - 84 + 120$

$16y = 36$

$y = \frac{36}{16}$

$y = \frac{9}{4}$