Question

please answer this not in a hurry but please​

Answer 1

Given

➝Distance between two buildings = 15x

➝Height of first Building = 12m

➝Angle of Elevation from top of the first Building to the top of second building is 30⁰

To Find

➝The height of the second building

Let

➝EC = x

➝Height of second building (BC) = x + 12

In △DEC

➝Tan30⁰ = EC/DE

➝1/√3 = x/15

➝x = 15/√3

➝x = 15/√3 × √3/√3

➝x = 15√3/3

➝x = 5√3

We get

➝Height of Second Building is (12+5√3)m

Answer

➝Height of Second Building is (12+5√3)m