Question

please answer this one​

Answer 1

value of a satisfying the equation is 3

Step-by-step explanation:

as we know prod of roots of quadratic equations = constant/coefficient of x^2

$1= \frac{6a}{a {}^{2} + 9}$

$a {}^{2} + 9 = 6a$

$a {}^{2} - 6a + 9 = 0 \\ \\ (a - 3) {}^{2} = 0 \\ \\ a = 3$