please answer this one
Attachments:
Answers
Answered by
1
Net force will be F cos theta + F sin theta
Fnet = 10×cos60 + 10× sin60
= 5+ 5√3
= 5(1+√3)
(ii) Vertical component of force = Fcos theta
= 10×cos 60
= 5
Hope this will help you ✌️
Mark as brainlist
Similar questions