Question

please answer this one

Answer 1

Hey dear your answer is here


100g100g of impure calcium carbonate contain :


=80g=80g pure calcium carbonate 


25g25g of impure calcium carbonate sample contain =80100×25=80100×25 


=20g=20g pure calcium carbonate 


The desired equation is: 


CaCO31mol100g+2HCl→CaCl2+CO222.4litreatNTP+H2OCaCO31mol100g+2HCl→CaCl2+CO222.4litreatNTP+H2O 


100g100gpure CaCO3CaCO3 liberate = 22.4 litre CO2CO2


20g20g pure CaCO3CaCO3 liberate =22.4100×20=22.4100×20


=4.48 litre CO2=4.48 litre CO2 

I hope you understand clearly

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