Question

please answer this
please answer​

Answer 1

Solution

1.total distance traveled by p = area of ∆PQR

= 1/2*4*6=>12m

total distance traveled by q=area of RQSO

=4*3=12m

there fore =>12-12=0

difference in the distance=12-0=12

2.yes, they move with same speed equal 3m/s

time in 2s. it can be determined by to the few insection point of two v/t graphs .

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