Question

please answer this please please​

Answer 1

it is board exam question

Answer 2

V = 3V

Let resistors are R¹ = R² = 12Ω each

1). Minimum resistance is when resistors are connected in parallel arrangements

Therefore,

1/R = 1/R¹ + 1/R²

1/R = 1/12 + 1/12

1/R = 2/12

1/R = 1/6

So, R = 6Ω

Equivalent resistance is 6Ω

P = V² / R

P = 3² / 6

P = 9 / 6

P = 3 / 2

So, P_2 = 1.5 W

2). Maximum resistance is when the resistors are connected in series arrangements

Therefore,

R = R¹ + R²

R = 12 + 12

So, R = 24Ω

Equivalent resistance is 24Ω

P = V² / R

P = 3² / 24

P = 9 / 24

P = 3 / 8

So, P_1 = 0.375

Ratio of P_1 & P_2 is

P_1 : P_2 = 1.5 : 0.375

P_1 : P_2 = 4 : 1

Hope this helps!

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