Question

. Please answer this problem i will mark u the brainliest if u answer me please it is urgent

Answer 1

Just follow the picture

Answer 2

In ∆ABD
AB=15cm
BD=9cm
In ∆ABD
AB^2 =BD^2+AD^2
225=81+BD^2
BD^2=144
BD=12cm
ar ∆ABD =(1/2)bh
$= \frac{1}{2} \times 9 \times 12$
Now ar∆ABC=2×∆ABD
$= 2 \times \frac{1}{2} \times 9 \times 12 \\ = 9 \times 12 \\ = 108\: {cm}^{2}$