please answer this qn 17 and 18 solve for x
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Answer:
17. x = 2
18. x⁴ + 1 -3x³ + 3x - 2x² = 0
Step-by-step explanation:
17. 4 (x - 1/x)² - 4(x + 1/x) + 1 = 0
4 (x² + (1/x²) ) - 4(x² + (1/ x)) + 1 = 0
4 (x⁴ +1 / x²) - 4(x² + (1/ x)) + 1 = 0
(4x⁴ + 4)/x² - 4(x³ + 1/x) + 1 = 0
(4x⁴ + 4)/x² - (4x³ +4)/x = -1
4x⁴ + 4 - 4x⁴ - 4x / x² = -1
4 - 4x = -x²
x² - 4x + 4 = 0
x² -2x -2x + 4 = 0
x(x - 2) -2 (x - 2) = 0
(x-2)(x-2) = 0
x- 2 = 0
x = 2
18. (x² + 1/x²) -3 (x - 1/x) - 2 = 0
(x⁴ + 1)/x² -3 (x² - 1/x) = 2
(x⁴ + 1)/x² - (3x² -3/x) = 2
(x⁴ + 1 -3x³ + 3x)/x² = 2
x⁴ + 1 -3x³ + 3x = 2x²
x⁴ + 1 -3x³ + 3x - 2x² = 0
Solve next by your own *_*
it's take a lot time
have a nice day !!!
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