Math, asked by resmikr1981, 5 months ago

please answer this qn 17 and 18 solve for x​

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Answered by Sirat4
0

Answer:

17. x = 2

18. x⁴ + 1 -3x³ + 3x - 2x² = 0

Step-by-step explanation:

17. 4 (x - 1/x)² - 4(x + 1/x) + 1 = 0

    4 (x² + (1/x²) ) - 4(x² + (1/ x)) + 1 = 0

    4 (x⁴ +1 / x²)  - 4(x² + (1/ x)) + 1 = 0

    (4x⁴ + 4)/x² - 4(x³ + 1/x) + 1 = 0

    (4x⁴ + 4)/x²  - (4x³ +4)/x = -1

    4x⁴ + 4 - 4x⁴ - 4x / x² = -1

       4 - 4x = -x²

    x² - 4x + 4 = 0

    x² -2x -2x + 4 = 0

   x(x - 2) -2 (x - 2) = 0

   (x-2)(x-2) = 0

    x- 2 = 0

    x = 2

18. (x² + 1/x²)  -3 (x - 1/x) - 2 = 0

      (x⁴ + 1)/x²  -3 (x² - 1/x)  = 2

      (x⁴ + 1)/x²  - (3x² -3/x) = 2

         (x⁴ + 1 -3x³ + 3x)/x² = 2

         x⁴ + 1 -3x³ + 3x = 2x²

         x⁴ + 1 -3x³ + 3x - 2x² = 0

Solve next by your own *_*

it's take a lot time

have a nice day !!!

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