Question

please answer this queation​

Answer 1

In triangle DPC and PBC

PC= PC ( common)

DC=BC(Side of sq.)

PD=PB(given)

So, triangle PDC congruents to PBC

Thus, Angle PDC= Angle BPC (CPCT)-(1)

similarly, triangle DAP congruents to PAB

So, Angle DPA=Angle APB (CPCT)--(2)

Angle DPA+ Angle DPC +Angle BPC +Angle APB=360

2(Angle DPA+DPC) =360, From (1) n(2)

Angle DPC+ Angle DPA =180 degree

So, CPA is a straight line

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